UPSC CSE Prelims 2026
The correct option is C - Both I and II.
[as per provisional answerkey]Let the five positions on the rods be 1, 2, 3, 4, and 5. Since the rods are identical and kept parallel, the positions for P and Q correspond directly (e.g., if P1 is at position 1, it matches with whatever Q is at position 1).
Given Constraints:
1. P1 matches Q3. (P1 and Q3 are at the same position).
2. P4 matches Q1 or Q2.
3. Q4 matches P3 or P5.
4. Q3 and Q5 are adjacent.
5. There are 5 distinct colors/parts: {P1, P2, P3, P4, P5} and {Q1, Q2, Q3, Q4, Q5}.
Testing Statement I: Q3 is at the middle (Position 3).
If Q3 is at position 3, then P1 is also at position 3.
Since Q3 and Q5 are adjacent, Q5 must be at position 2 or 4. Let's assume Q5 is at position 4.
Now we need to place Q4. Q4 matches P3 or P5. Let's place Q4 at position 1.
Now we check P4. P4 matches Q1 or Q2. If we place Q1 at position 5, P4 can be at position 5.
This leaves Q2 at position 2.
Arrangement:
Position: 1 - 2 - 3 - 4 - 5
Rod Q: Q4 - Q2 - Q3 - Q5 - Q1
Rod P: P3 - P2 - P1 - P5 - P4
Check: P1 matches Q3 (Yes), P4 matches Q1 (Yes), Q4 matches P3 (Yes), Q3/Q5 adjacent (Yes).
Conclusion: Statement I is possible.
Testing Statement II: P2 is at an extreme (Position 1 or 5).
Let's try placing P2 at position 1.
If P2 is at position 1, then Q must have a value there (say Q4).
If Q4 is at position 1, it must match P3 or P5. Let's say P3 is at position 1. But we just placed P2 there. This is a contradiction.
Wait, let's try another configuration:
Position: 1 - 2 - 3 - 4 - 5
Rod P: P2 - P4 - P1 - P3 - P5
Rod Q: Q4 - Q1 - Q3 - Q5 - Q2
Check:
1. P1 matches Q3? Yes (Position 3).
2. P4 matches Q1 or Q2? Yes (P4 matches Q1 at Position 2).
3. Q4 matches P3 or P5? Yes (Q4 matches P2... wait, let's adjust).
Let's try:
Rod P: P2 - P3 - P1 - P4 - P5
Rod Q: Q2 - Q4 - Q3 - Q1 - Q5
Check:
1. P1 matches Q3 (Pos 3).
2. P4 matches Q1 (Pos 4).
3. Q4 matches P3 (Pos 2).
4. Q3 and Q5 are adjacent? No (Q3 is at 3, Q5 is at 5).
Let's adjust: Rod Q: Q2 - Q5 - Q3 - Q4 - Q1.
Rod P: P2 - P5 - P1 - P3 - P4.
Check: P1=Q3 (Pos 3), P4=Q1 (Pos 5), Q4=P3 (Pos 4), Q3/Q5 adjacent (Pos 3 & 2).
In this valid case, P2 is at Position 1 (Extreme).
Conclusion: Statement II is possible.
Logical consistency and existence of permutations under multiple constraints.