Maths : Basic Numeracy

Q 30 / 370

UPSC CSE Prelims 2026

In an objective type question paper, 5 marks are awarded for a correct answer and 2 marks are deducted for a wrong answer. A student attempted all the questions and got a score of 69. Had he been awarded 4 marks for a correct answer and 1 mark deducted for a wrong answer, he would have scored 84. How many questions were there in the question paper?

EXPLANATION

The correct option is B - 81.

[as per provisional answerkey]

Solution

Let the number of correct answers be x and the number of wrong answers be y. Since the student attempted all questions, the total number of questions is (x+y).

Step 1: Formulate equations based on the given conditions.
Case 1: 5 marks for correct, 2 marks deducted for wrong. Score = 69.
5x−2y=69 - (Equation 1)

Case 2: 4 marks for correct, 1 mark deducted for wrong. Score = 84.
4x−1y=84 - (Equation 2)

Step 2: Solve the system of linear equations.
From Equation 2, we can express y in terms of x:
y=4x−84

Substitute this value of y into Equation 1:
5x−2(4x−84)=69
5x−8x+168=69
−3x=69−168
−3x=−99
x=33

Now, find the value of y using x=33:
y=4(33)−84
y=132−84
y=48

Step 3: Calculate the total number of questions.
Total questions = x+y
Total questions = 33+48=81.

Why the other options are incorrect

  • Option (a) - 99: This value does not satisfy the simultaneous equations; if total questions were 99, the scores would not align with the 69/84 results given.
  • Option (c) - 84: This is the score mentioned in the second scenario, not the total number of questions.
  • Option (d) - 79: This value results from a calculation error or incorrect substitution in the linear equations.

Key Concept

Solving a system of linear equations in two variables to determine unknown quantities based on multiple scoring scenarios.