Question: Let P, Q, R, S be distinct non-zero digits. If PP × PQ = RRSS, where P ≤ 3 and Q ≤ 4, then what is Q equal to?
Which one of the following is correct in respect of the above Question and the Statements?
The problem requires determining the value of Q from the equation PP × PQ = RRSS, given that P, Q, R, S are distinct non-zero digits, with P ≤ 3 and Q ≤ 4.
The given equation can be translated into an algebraic form:
Substituting these into the equation yields: 11P × (10P + Q) = 1100R + 11S.
Dividing both sides of the equation by 11 simplifies it to: P(10P + Q) = 100R + S.
Now, we apply the given constraints:
Let's test the possible values for P:
Substitute P = 3 into the simplified equation: 3(10 × 3 + Q) = 100R + S, which simplifies to 3(30 + Q) = 100R + S.
Next, consider the constraints for Q:
Let's test these possible values for Q:
The unique set of distinct non-zero digits that satisfies all conditions is P=3, Q=4, R=1, S=2. These values also satisfy P ≤ 3 and Q ≤ 4.
Since Q = 4 is uniquely determined using only the information provided in the question, neither Statement I (R=1) nor Statement II (S=2) is necessary to answer the question.
Options 1, 2, and 3 are incorrect because the value of Q can be definitively established through a systematic analysis of the given equation and its constraints alone. The information provided in Statement I (R=1) and Statement II (S=2) is consistent with the derived solution but not required for its determination.