UPSC CSE Prelims 2017
Let the 2-digit number be represented as , where is the tens digit and is the units digit. For both the original number and its reverse to be valid 2-digit numbers, both and must be integers from 1 to 9 (i.e., ).
The reversed number will be .
The problem requires dividing the larger of these two numbers by the smaller one. Let be the smaller number (divisor) and be the remainder. According to the properties of division, the remainder must satisfy .
To identify the largest possible remainder, we should consider scenarios where the divisor is relatively large, allowing for a larger potential remainder that is just below . Given the options, the maximum possible remainder is likely to be 45. If the remainder is 45, the divisor must be at least 46.
We systematically examine pairs of numbers where the smaller number (divisor ) is 46 or greater:
Further examination of other relevant pairs confirms that 45 is the maximum remainder:
The largest remainder obtained through this systematic analysis is 45.
Option A (9): A remainder of 9 is a possible outcome (e.g., 98 divided by 89 yields a remainder of 9). However, this is not the largest possible remainder.
Option B (27): A remainder of 27 is a possible outcome (e.g., 96 divided by 69 yields a remainder of 27). This is not the largest possible remainder.
Option C (36): A remainder of 36 is a possible outcome (e.g., 95 divided by 59 yields a remainder of 36). This is not the largest possible remainder.