Maths : Data Interpretation

Q 28 / 46

UPSC CSE Prelims 2014

The following table shows the marks obtained by two students in different subjects:

Student A Maximum marks Student B Maximum marks
English 60 100 80 150
Psychology 70 100 70 100
History 50 100 60 100
Sanskrit 30 50 15 25

The difference in the mean aggregate percentage marks of the students is

EXPLANATION

Correct Option

To determine the difference in the mean aggregate percentage marks, the total marks obtained and the total maximum marks for each student must first be calculated.

For Student A:

  • Total marks obtained = 60 (English) + 70 (Psychology) + 50 (History) + 30 (Sanskrit) = 210
  • Total maximum marks = 100 (English) + 100 (Psychology) + 100 (History) + 50 (Sanskrit) = 350
  • Aggregate percentage for Student A = 210350×100 = 60%

For Student B:

  • Total marks obtained = 80 (English) + 70 (Psychology) + 60 (History) + 15 (Sanskrit) = 225
  • Total maximum marks = 150 (English) + 100 (Psychology) + 100 (History) + 25 (Sanskrit) = 375
  • Aggregate percentage for Student B = 225375×100 = 60%

The difference in the mean aggregate percentage marks of the students is:

  • Difference = Percentage of Student A - Percentage of Student B = 60% - 60% = 0%

Therefore, the difference is Zero.

Incorrect Options

Options 1 (2.5%), 2 (13.75%), and 3 (1.25%) are incorrect because the calculated aggregate percentage for both Student A and Student B is 60%. The difference between these two percentages is 0%, not any of the values provided in these options.